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Willy1729
Willy1729
11 months ago

Hello,

(1-p)^k is the counter probability for at least one, namely none at all. If a passenger with a probability of p voluntarily shifts his flight, he does not do that to 1-p probability.

If you are talking to k passengers, the probability is calculated to get a cancellation from all to (1-p)^k – all refuse to postpone the flight.

If you take this off from 1, all other possible events occur, so at least one can be asked. Therefore 1-(1-p)^k.

Best regards,

Willy

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GuteAntwort2021
GuteAntwort2021
11 months ago

Hello.

The term corresponds to the described description.

In the task section beforehand, p is described with the probability that a passenger is ready to take a later flight.

1-p therefore gives the probability that a passenger is not willing to do so.

(1-p)^k according to the probability that k passengers successively interrogated all not want to take the later flight. And what is the counter probability of the event -> 1 – (1-p)^k?

Exactly that at least 1 passenger would be ready to take a later flight.

LG

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