ByArian88
Hey, the task is:
Calculate the total area between the graph and the x-axis. The function is: f(x) = 3x^(2) + 4x-1.
This is my solution to the following task:
Is my result correct?
Thank you.
(1 votes)
Loading...Hello, we have an exam on Friday, and I wanted to prepare a little. Unfortunately, our teacher doesn't give us any workable problems; we're supposed to come up with our own. I wanted to calculate the FE of the fish and was wondering if that's correct? I copied the left shift from the board… would…
Hello, I have a math test tomorrow and I'm not sure if my answer to question b) is correct. Thank you in advance!
Draw a circle with radius r = 4cm. Construct a triangle whose vertices are all lie on the circle, with b) c = 7.5 cm, a = 15°. a) a = 5 cm, c = 7 cm, Construct a triangle with circumradius r from a) r = 4.5 cm, c = 7 cm, B =…
and could you maybe take a look at my last question, it's about a TI-nspire calculator
A big thank you to everyone in advance!
No, it’s not right. Zero points, master function all the above (good in the master function still lacks +C as a constant but is assumed here 0 anyway. You seem to have entered something wrong in the calculator. Upper border minus lower comes out – 0.11 – 2.63 = – 2.74 FE.
You can see that it can’t be 15 if you look at the surface of the parabola to the X axis. The space would be almost 4×4, i.e. from Y2 to −2 and from X0 to −4 for example.
Okay, thank you. But my solution is correct, right? I just tipped myself, the rest is correct, right?
which rest? 15 FE is completely too much
Except for the +C. The f(x) small zero makes no sense, you need to derive the function first to determine minima or maxima and then set f’ zero there. That’s how you determined the intersection with the y axis.
not at all. How to find yourself when plotting f(x) times
never and never are that over 15 FE!
the boundaries are also quite stupid, unhandy numbers .
like you here
it writes, you probably went on with the TR and made mistakes. TR – Input Practice !
so it should be
At 2. Still missing where the function value is now negative and where positive is
What do you think I had written that the interval f(x) is <0?
Is my final result ultimately true?
Okay, thank you. Is my final result ultimately true?
Here my correction: