In the radical substitution reaction, the H atom is attracted to the halogen radical in the first chain propagation step.
Why is that ? And what about the halogen bromine?
(Hydrogen atom of the alkane on the right side is attracted to the halogen Cl)
(1 votes)
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Are 2-butene and but-2-ene the same? Or, what is the direction, and which is used more frequently?
There are supposed to be 5, but I don't see any different substituents here… LG
Have virtual particles ever been empirically proven or are they just a mathematical concept?
It forms when it's cold. Everything turns white. It melts when it gets hot.
In the case of chlorine, it should be quite clear – the electronegativity of chlorine is significantly higher than that of carbon, so it is to be expected that chlorine can also bind protons (hydrogen ions).
In the case of bromine, it is more complicated – in this case, even energy must be used in order to transfer an H to the Br radical. After all, in the microcosm, everything that can happen in any way happens only the less often, the more energy (or comparable) it costs, and then it will be reversed more quickly.
(See the results of a web search by
radical substitution brom
probably the hit
https://www.studysmarter.de/schule/chemie/organic-chemie/radikalische-substitution/
suitable to understand a little more.)
If a sufficiently stable end product is produced, one has luck – then there is enough left of the end product.