Question about electrical engineering – conductor resistance?
First, I need to calculate my conductor resistance using the formula R=l/x*A, right? How do I solve this problem?
First, I need to calculate my conductor resistance using the formula R=l/x*A, right? How do I solve this problem?
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The formula for resistance is correct. However, it is necessary to set for a length of 180 m, because the current also has to flow back.
Then you know the resistance.
The rated power is 8000 W, which refers to 230 V rated voltage. You can calculate the denominator.
The voltage drop in the conductor is calculated from resistor and rated current. And this is subtracted from the measured 232 volts.
What are these 3x?
A is the cross-sectional area of the conductor, i.e. 6 mm2.
The 3 x in front means that there are three such conductors in the cable.
NYY means a PVC-insulated earth cable.
You can use 6 mm2 directly for A. And for the length of 180 m. It is not necessary to convert because in the specific conductivity there are also mm2 and m.
You can ignore the 3 x, which is only for information. There are, for example, also NYY 5 x 6 mm2, there are then 5 such conductors (used for three-phase current).
So I just have to use 6mm in the formula? Or convert to meters? And I ignore the 3x?
If one follows the simple formulas of the table books, then 213,204 V are obtained.
But actually, you have to expect something more complicated here:
Calculate conductor resistance, load resistance and total resistance.
This allows the proportional voltage to be determined at the consumer.
This results in the voltage at the consumer:
By the way:
The voltage drop is 7.494%. The conductor cross section is thus too small.