Determine extreme points using the 2nd derivative?
If a function is given and I have found the 1st and 2nd derivative and know both zeros, I then have to calculate the y-axis intercept again. If the task is to determine the local extreme points
If a function is given and I have found the 1st and 2nd derivative and know both zeros, I then have to calculate the y-axis intercept again. If the task is to determine the local extreme points
Hello, this is MSA 2017. I need help with task 3a). I've completely forgotten how it all worked. Can someone please explain it to me and help me?
It's about task 1. I'm starting my master's degree in July and am currently calculating the tasks for the master's degree using documents from someone I know, but I'm stuck on this task. Maybe I'm just thinking too complicatedly, which is why I'm asking the question here. I appreciate any help and thank you in…
Good day 🙂 I've been given a few math problems and I'm not quite sure how to proceed with this calculation. If anyone has a solution, that would be a huge help. Thanks in advance! 😀 A three-sided pyramid has the base ABC with A(1; -1;-2), B(5;3;-2), C(-1;6; -2) and the vertex S(2; 3;4): c)…
In this parabola, if you insert the given points into a system of equations and apply the addition method, you get 0 at any point ax and bx, which is what you need to find. How do I proceed here?
Hi, I need to use the points P(-2|5) and Q(2|20) to find a and q from the formula f(x)=a•q^x. Can someone help me and explain the calculation?
The necessary condition for local extreme points is f'(x)=0
If this x also applies f”(x) <> 0, you have found an extreme place. Set the x in f(x) and you have the extreme E(x|f(x))
<> shall mean “unequal”
No, you will only determine the y-axis section if it is searched for according to the task. He’s not one of the Extrema.