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YBCO123
2 years ago

“Brute Force”: Place stitches and knot equations to Kirchhoff.

Or you convert the branches between the nodes A-C and C-B by equivalent sources to make the external current sources Ia, Ib, Ic equivalent voltage sources. These are one, two steps you can count in your head when you make sketches.

Step-1: Recharging external currents

Schtitt-2: Uq2, R2 convert into a power source:

Shtitt-3: Collecting currents

Step 4: Converting the current sources into voltage sources

In the end, the circuit is characterized by:

For the nodes A, B, C, D, there is no difference with respect to the potentials set, since there are respective substitute sources equivalent to the original circuit between them.

Then you realize that the current in this circle

I4=I1=60V/16Ohm=3,75A

is -> the other streams you get easily and are ready:

I2=3,75A-6A=-2,25A

I3=8A-3,75A = 4,25A

.