Electron negativity of ammonia?

Hi, the internet says the electron negativity of ammonia is 3.04. But how is that possible? I thought you had to take the molecular formula, NH3, and then subtract 3.0 from H, which is 3.0 – (3•2.1). How do you do that correctly, or why is it 3.0? Thanks!

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MeisterRuelps, UserMod Light

on the Internet, the electron-negativity of ammonia would be 3.04. But how can that be?

No, there is no! – Elements possess an EN value that reflects the desire to remove electron(density) from another atom.

I thought it was necessary to take the sum formula NH3 and then take off N 3.0 from H so 3.0 – (3•2,1)

Then you thought wrong. You look at the bonds between the individual atoms and determine the difference there. These numbers can then be used to determine whether a partial charge is present, etc.

Alex1735
1 year ago

Hello sophiareich19,

The electronegativity of N is with me 3.04. H is 2.2. That means that

ΔEN(N,H)= 3.0 – 2.1 = 0.84.

You do not calculate H three times but only once so that you can see if it is a dipole or not a trade, and where d- or d+ is.

JenerDerBleibt
1 year ago

There is no electronegativity of compounds therefore also not of ammonia! Electronegativities exist only for atoms. And with this one calculates the electro-negstivityDifference of a single Bond out.

TomRichter
1 year ago

on the Internet, the electron-negativity of ammonia would be 3.04.

The Internet also states that “on the Internet” is not a meaningful source. And that’s true, unlike the statement about NH3

Only atoms have an EN. Bindings have an EN difference. Verificationhave none of them.