Electron-electron collision completely elastic?
Electron 1 flies with the speed v = 50 meters/second
Electron 2 flies with the speed v = 50 meters/second
The electrons fly directly towards each other, collide at a 180° angle, and fly away from each other again at a 180° angle in the opposite direction.
What is the speed of electron 1 and electron 2 after the collision?
Is the collision perfectly elastic?
(0 rating, 0 votes, rated)You need to be a registered member to rate this.
Loading...
Electron-electron scattering is called Møller scattering.
first approach is the process elastic.
in higher order of the disorder theory, of course, the radiation of photons also occurs.
Accelerated charges emit electromagnetic waves. So the bump must be inelastic. However, according to current knowledge, electrons are punctiform. This makes it impossible to make them meet exactly. The question becomes physically insane.
Accelerated charges emit electromagnetic waves
If the impact is full elastic and the kinetic energy after impact is the same?
This makes it impossible to make them meet exactly
What do you mean?
There were electron-pistron collisions in particle accelerators. I don't know whether there were electron collisions, but maybe they did.
The shock ionization in the gas discharge tube is based on electron-electron shocks.
An electron-positron collision is something else, because the two draw each other because of the unequal charges. With two electrons, however, an almost infinitely small deviation from the central impact is sufficient to allow the two to escape.
This is not possible. The conclusion as a premise is not meaningful. One example: "Is there a unicorn when collapsing a gold and a carbon atom in which a unicorn is formed?" Sure?
Point has extension 0
Extension 0 would be non-existent
Do you have a source indication for measuring an elastic impact between two electrodes with 180° backlash
It doesn't have to be 180° in the experiment. It would then be able to be calculated for 180° by a formula. If it could be calculated. Electron-electron scattering is easy to observe with the Compton effect
Photon is scattered on electrons during the Compton scattering. You mean something else?
"As a Compton effect, the magnification of the wavelength of a photon while scattering on a particle"
No. Point has the extension 0.
You probably mean "apparently," not "apparently."
Do you have a source indication for measuring an elastic impact between two electrodes with 180° backlash? How would you mark the electrons to filter out the events where the electrons flew past each other with 0° scatter?
Electron-electron scattering is easy to observe in the Compton effect, even without particle accelerator.
however, an almost infinitely small deviation from the central bump is sufficient to allow the two to escape.
But it would theoretically be possible to shoot two electron beams with a large number of electrons to meet each other. Even if it is a point, this point has an extent and cannot be 0
Asking the conclusion as a premise
No, that was not, but if the experimental observation is that the kinetic energy after the shock is the same, the electrons do not radiate electromagnetic waves.
But it seems to you that there were electron collisions in particle accelerators.