Electron configurations?

Hello dear people,

So I have an equation like that and I can use it to explain some of the contradictions in our physics!

I discovered through my equation that everything microscopic follows the same rules as macroscopic.

When I compare a solar system with the periodic table I immediately notice the orbital problem of the electron configurations!

According to my reasoning, no two electrons can be in the same orbit, let alone 3 or 10….

11²=121, 111²=12321, 1111²=1234321

According to my mathematics and observations of the planetary system, there should not be more electrons there, but heavier ones.

For example, have you noticed that in all solar systems the heavy gas planets are always distributed centrally in the orbits of planets and never at the edge?

If several electrons were to use an orbital, they would collide, which can be deduced from observations of the planetary system.

So I ask you all quite cheekily: is the electron configuration of the periodic table wrong?

Are elementary orbitals really the same as planetary orbitals?

(3 votes)
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pchem
3 months ago

The chemical orbital model has nothing to do with the planet model. The celestial body is described with mechanical equations of motion – on the other hand, electrons are described with wave functions (which result as solutions of the Schröding equation).

An orbit/orbital path is a sharply defined track in the space – an orbital is, on the other hand, an area in the space in which electrons are to be found to a certain probability.

An atomic analogue to the planet model is the drill atom model. With this one can be e.g. the spectral lines of hydrogen, but for higher purposes (e.g. the explanation of the chemical bond) it is unsuitable and here the orbital model is instead the means of choice.

pchem
3 months ago
Reply to  Rusigtr89

If you find them funny, nature doesn’t matter.

pchem
3 months ago

100/99 = 1,0101010101

I see what you mean, there are 2 nine in the denominator, and the result is the number 1 in every 2nd place. But what are you doing? On the one hand, this is not a new theory, and on the other hand it is quite impractical to show waves, since one can only represent wavelengths corresponding to natural numbers (1, 2, 3,…). What if the wavelength does not correspond to a natural number? That is, as in almost any real application?

It’s a nice number playing, but it’s the existence of Perpetua mobilia to derive from it or to dismiss quantum physics as a false one, it’s still unstoppable.

pchem
3 months ago

Can you model with your equation a), b) and c)?

pchem
3 months ago

In her investigation I found that each wave with her modeling can and she describes a universal wave law!

Well, how would you “model” the following waves with your equation?

a) y = 2 • sin(x + 5)

b) y = 4 • sin(x + 3)

c) y = 2 • sin(x + 5) + 4 • sin(x + 3)

pchem
3 months ago

Both the microscopic and the macroscopic follow the energy conservation set!

I’m glad you came to this knowledge. In your other post you defended the existence of Perpetua mobilia…

Physikraxi
3 months ago

Whatever the others will answer is wrong insofar as the geometry of the current model of conception is based on a four-dimensional geometry, but is often calculated and assessed only three-dimensionally.

Partly this is taken into account, but not complete. Thus, for example, the time dilatation basically follows a four-dimensional model, but the assessment of what would be correct or wrong is assessed exclusively under three-dimensionally conceivable criteria, but calculated in 4D.

But here on good question.de it is not possible to explain such complex relationships, because this medium is absolutely inappropriate to explain it here. The text of the answer is limited and, for example, the simplest graphic possibilities such as animated GIF images that could illustrate the text differentially geometrically.

According to my consideration, no two electrons can be found on the rare orbit, let alone the 3 or 10….

This assumption is therefore wrong, because they can obviously superposition from the 3D perspective, because they are located in a 4D environment, where they are always located next to each other in reality, etc.

Physikraxi
3 months ago
Reply to  Rusigtr89

Jesus Christ, what a wonderful imagination you have, and with that you are superior to me, who considers himself an absolutely sloping cross-bearer. It is therefore not possible for me to reply reasonably to so much mischief.

Physikraxi
3 months ago
Reply to  Rusigtr89

My text is the same as your comment.

Benni142
3 months ago

No the period system and the electron configurations therein are correct. It is almost general knowledge that particles in the microscopic also act like waves and also vice versa (wave parts dualism).

And according to current state of knowledge, e.g. Electrons distributed in atoms with probabilities whose probability of residence is indicated by the orbitals. Super many devices are based on quantum mechanics and the power of these laws is virtually unchallenged.

Benni142
3 months ago
Reply to  Rusigtr89

For the first statement I can say nix.

Secondly, do you mean the coulomb sourcing that the force is proportional to 1/r^2? This would then be indirectly proportional.

With the Higgsfeld, I know too little to say when it dissolves. I thought it was a constant field that gives all the particles its mass.

Why don’t you describe your equation, which explains some contradictions of physics that you mentioned in your question. That would help to understand what you actually did. But I think it’s almost impossible for what you say to be true

Benni142
2 months ago

We can determine the position of the electron quite accurately. Or what do you mean that the electrons take the position too short and therefore appear wave-shaped to us?

To the equation, that’s no equation, that’s just numbers where the 9 stands for one revolution per time, so speed? Huh? Give me the right equation.

And how does the third newtonian axiom play in now??

EternalEndo
3 months ago

I think this is a little different and move in shells and not gear exactly on one track and at their speed they create a negative space rather than negative rows. It’s not the case with planets.

If you understand what I mean and if I understood what you mean 👈