Why is magnesium only allowed to have 2 electrons in the K shell, 8 electrons in the L shell, and 2 electrons in the M shell? How can I determine this, for example, in the case of sulfur or phosphorus?
(1 votes)
Loading...The reduction occurs because Cl gains two electrons. But how do I plot the oxidation? Since O isn't even present on the reactant side…
is it: 2Na + Cl2 -> 2 NaCl or Na + Cl -> NaCl
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For the shells from the inside to the outside:
e(max)=2×n2
2, 8, 18, 32, 50, 72, …
On the outer shell, however, only 8 e may be on the 2nd outer shell 18, then 32.
As a result, the main groups IMMER are as many e on the outer shell as the HG No. And there are always as many bowls as the periods No
This is such a question where one should say clearly at a certain level of schooling and learning: do not try to understand it at all, because you (still) lack all the backgrounds and methods. In the end, this is due to energy levels based on quantum physics, spin rules and blabla …
Only nobody says loudly and openly that you have to know this first (so learn) because in mathematics, physics and chemistry you always understand everything.
(And now I expect the opposite votes)
It took a while, but:
The fact that the shell number n can hold a maximum of 2n2 electrons is said continuously here at least. And in the case of magnesium there is not yet the complication that the filling does not take place cleanly in series.
In school, the difference between the period and the shell is often blurred, so that the perials or the formiodes (coffer word) 2, 8, 16, 32 and 32 electrons capture. And we fight against windmills because every attentive student from the scandium no longer understands the world.