Electrical engineering: Calculate current?
Hello
I have a question about the following task
In this task, you have to calculate the current. I came up with 0.48 A, but I strongly believe that's not possible. Can anyone help me?
Would be great๐๐
Hello
I have a question about the following task
In this task, you have to calculate the current. I came up with 0.48 A, but I strongly believe that's not possible. Can anyone help me?
Would be great๐๐
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So here on the NDS coast the sun is still shining at 23ยฐC, how warm is it where you are?
You must also consider the resistance of the lamp (24V, 36W).
It applies to the lamp
Performance P = U*I or if I is replaced by I = U/R
is P = U*U/R converted to R
R = U*U/P (for the lamp with 24V and 36W)
now calculate resistance of the lamp R = 24V * 24V / 36W = …
Then the thus determined resistor R of the lamp coincide (it is a parallel connection!)
Rges = 50 Ohm || R = …
Formula for performance P:
https://www.elektronik-kompendium.de/sites/grd/0201114.htm
Good luck!
Thank you for your help.
The total current is Iges = 1.98 A, so you can compare your result.
PS: There are several computing paths for this solution.
Good luck!
This is a mixed circuit – and you can find enough on the Internet! You first calculate the lamp current and then add the current of the two series resistors.
Lamp current: I = root from P/R
Resistance current: I = 24V : (R1+R2)
Thanks for the help๐๐
0.48 A is the current which flows at 24 V through the resistors below (together 50 ohms). The lamp comes in parallel with 1.5 A (36 W at 24 V). The two parallel currents are added.
…or so…
Did I help you?
That’s right. But only if the pear is broken.
First, assemble the 2 resistors (have you already made), the resistance of the pear, and then you can calculate the total resistance of the parallel connection of combined resistance and pear and then the current over it.
Thank you for your help