Electrical engineering: Calculate current?

Hello

I have a question about the following task

In this task, you have to calculate the current. I came up with 0.48 A, but I strongly believe that's not possible. Can anyone help me?

Would be great๐Ÿ‘๐Ÿ˜…

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Transistor3055
1 year ago

You must also consider the resistance of the lamp (24V, 36W).

It applies to the lamp

Performance P = U*I or if I is replaced by I = U/R

is P = U*U/R converted to R

R = U*U/P (for the lamp with 24V and 36W)

now calculate resistance of the lamp R = 24V * 24V / 36W = …

Then the thus determined resistor R of the lamp coincide (it is a parallel connection!)

Rges = 50 Ohm || R = …

Formula for performance P:

https://www.elektronik-kompendium.de/sites/grd/0201114.htm

Good luck!

Transistor3055
1 year ago
Reply to  Dene123

The total current is Iges = 1.98 A, so you can compare your result.

PS: There are several computing paths for this solution.

  • About the overall resistance as I described it
  • Or via the substreams 1.5A (lamp) + 0.48A (via the 2 resistors)

Good luck!

Gluglu
1 year ago

This is a mixed circuit – and you can find enough on the Internet! You first calculate the lamp current and then add the current of the two series resistors.

Lamp current: I = root from P/R

Resistance current: I = 24V : (R1+R2)

Ralph1952
1 year ago

0.48 A is the current which flows at 24 V through the resistors below (together 50 ohms). The lamp comes in parallel with 1.5 A (36 W at 24 V). The two parallel currents are added.

easylife2
1 year ago
Reply to  Ralph1952

…or so…

easylife2
1 year ago

That’s right. But only if the pear is broken.

First, assemble the 2 resistors (have you already made), the resistance of the pear, and then you can calculate the total resistance of the parallel connection of combined resistance and pear and then the current over it.