Mit 2 gegebenen Geschwindigkeiten.
Weil eigentlich rechnet man da ja die Mitte der Beiden Geschwindigkeiten aus, aber mir wurde gesagt, dass sei falsch.
(No Ratings Yet)
Loading...Kino Ticket Preis: 1 Erwachsener, 3 Kinder = 21€ Welcher Preis bei 3 Erwachsenen und 5 Kindern?
Ich möchte mehr Leistung aus einem 12V – 100Watt Gleichstromverbrauchers herausquetschen. Kann mir das durch Erhöhung der Spannung über 12V gelingen ?
Gutn Abend/morgen/mittag Zum Thema KV, wie fliegt es sich so ?: hoher pitch/wenig KV VS Wenig pitch/hoher KV ? Was könnt ihr mir mir da mit euren Erfahrungen sagen😁😁 Allerbesten Gruß🔛🔝
The average speed is Delta v
v=v_2-v_1
You have to subtract your speeds.
Note: v_2=4km/h
v_1=2km/h
Calculation v
Solution:
v=v_2-v_1= 4km/h-2km/h= 2km/h
The average speed is 2 km/h.
I added another example. If you have any questions, just ask. Hope you understood everything. :
And how is this in an acceleration? So if I’m accelerating from 50 to 100 km/h in 10s? How do I calculate the average speed and acceleration?
That’s what you’re supposed to do. 100km/h – 50km/h and then by 10s.
However, you have to convert km/h into m/s or the 10s into a student.
Since it is not specified how long you travel at the specified speeds (and therefore no travelled distance can be determined), no average speed can be determined only with indication of 2 speeds!
…and that:
“Solution:
v=v_2-v_1= 4km/h-2km/h= 2km/h
The average speed is 2 km/h.”
is unfortunately completely wrong. This is not an average, but only the difference between the two speeds.
…and acceleration doesn’t matter at all.
With the difference, he meant the dysfunctionality. That’s true with time too, I’m right to you. But the difference was meant here. Because at two given speeds no average speeds can be calculated, so it is self-explanatory that the difference is meant here. Before you accuse me for no reason, you should think more about what you’re writing here. He wanted to know the acceleration, which is why I added it.
“The acceleration he wanted to know later why I added this.”
What are you saying? I do not see anything in this regard,
My comment was also supported with helpful and thank you. I even got many more questions. With so many examples and answers to my answer, I assume that my is not wrong.
No – I asked again at the FS “for the sake of clarity” and wait for his/her answer. And since my answer has meanwhile also been marked by the FS as a “helpful kingdom”, I assume that he/she actually meant “average” – as I said, in the “question” there is no sign of “difference”.
Because you’re not answering, I assume you’ve recognized your mistake.
He used the wrong name. But in the description of his question it became clear that he meant the difference.
“With the difference, he meant the dysfunctionality.”
And what is the point of the question? There’s a clear talk about “average speed”, not about speed difference, right?
If you have any questions, you can ask them. I found another more beautiful representation. With this you understand it better with the initial speed etc.
OK, thank you!
Yeah.
Do you calculate DELTA v as well?
DELTA v/ DELTA
I found a page from one of my old books. I’ll put them in.
And if I did, how is the formula?
“…the middle of the two speeds…”
This is true only in the event that you have the same time at the specified speed – i.e. for 1 hour at 2km/h and then for one hour at 4km/h (then you would have reached 6km in 2 hours, corresponding to an average speed of 3km/h). If, however, the times are not identical (which is probably the case in most cases), one must first determine the route covered; this way divided by time is then the average speed.
For laying a certain distance, you need a certain amount of time – the average speed is determined from these two data, with which the distance was managed. If you increase your speed extremely during the course, in order to then move you further at low speed, it logically has no influence on the average speed as long as the time required overall remains the same.
The task must be specified:
Example:
The route s is 10 km
Case 1)
You drive 1/2 h with 5 km/h and 1/2 h with 15 km/h. It’s 10 km together.
Case 2)
You drive 5 km with 5 km/h and 5 km with 15 km/h. It’s about 10 km.
Consider why the average speed in these two cases is not the same.