Doubling radius?
"The diameter of a sphere is doubled. State the factor by which the volume changes."
Can someone please help me with a solution? Thanks.
"The diameter of a sphere is doubled. State the factor by which the volume changes."
Can someone please help me with a solution? Thanks.
Hello, Can someone give me some brief feedback on the solutions and, if something is wrong, how it could be improved. thanks in advance
When it comes to antisymmetry of relations, why don't we simply say "If A = B and B = A," then they are the same element, and how is that different from reflexivity? And if A < B and B < A are sufficient to assert antisymmetry, then what is equality in mathematics anyway?
Hello, what's the middle between 2/5 and 30/100, please? And 1/4 & 3/20? And 1/8 & 3/20? Thanks in advance
Hello! I have to draw an oblique view of a square pyramid with dimensions a=4.8cm and h=10.6cm. So far, everything seems pretty clear. But do I have to draw the actual height, or halve it to 5.3cm? Maybe a stupid question. The pyramid would then be enormous. And would I also have to use the…
Hey can someone explain to me step by step why C 6 H 14 + O 2 = CO 2 + H 2 O 2C6H14 + 19O2 = 12CO2 + 14H2O Balanced out, I'll say that I don't quite understand the oxygen thing
I don't understand the task. Can someone please help me with this as I will be getting a grade for it. This was what he told us in addition to solving the last equation "formally" (this, with some thought, yields a term that can ultimately(!) reveal the solutions we are looking for for m. Someone…
…
Write the formula for the volume. There’s a radius in it. Then you set for the radius in the formula 2r. Then look what happens to the two and you have your factor.
Volume goes with the third potency of the radius – with a doubling of the radius, the volume of a sphere increases…
The volume increases.
If you change the scale, it changes
Volume with the third potency. We double here,
and what is the third potency of 2?
You can also use the formula:
V = 4/3*pi*r3
Now, instead of 2r, you’re using:
V = 4/3*pi*(2r)3
How did V change now?