Does anyone understand this, if so can you explain it?
Please only answer my question, thanks π
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The purpose of the task is to recognize that the area cannot be of the same size when the entrance 1 is in operation. Previously square, i.e. as much area as possible with a given circumference. If one increases one side from a square and the other is reduced by the same amount, the area cannot be the same size.
(Next: By the way, you would get the most area with a given size, but this is not available here)
Step 1:
x2 = (x+4)*(x-4)
x2 = x2 -4x +4x -16
I can’t! There is no solution here, x2 and x cut out.
Step 2:
x2 = (x+6)*(x-4)
x2 = x2 -4x +6x -24
2x = 24
x = 12
This went up when the area was 12 m * 12 m = 144 m2.
The new area would then be 144 m2 with 18 m * 8 m.
If you take the square 144m2 area for entry 1 as an example, you can see:
A = 16 m * 8 m = 128 m2 (in this case the broker is cheated by 16 m2)
Note: 4*6 = 24 and not 16
Yes, already corrected, was copy from entry 1, but thank you!
Thank you very much! You helped me very much π
I agree 100%. In this case, however, the “activity” was less in the account than to see where the purpose of the task is at all. Therefore I decided here to complete the task incl. Explanatory notes. If, of course, one does not do it in principle.
Note: If such pupil questions are answered in the same way as the complete deletion of the task, this is very practical for the pupil at the moment, but overall, this leads only in the long term to increasingly lower knowledge and skills among the pupils. “Brave new world”
The area of the original plot A = a^2 m2.
The first offer (a-4) * (a+4) has a smaller area of 16 m2.
The second offer has the same area content if a has a very specific value.
I don’t understand, is not possible
My question wasn’t whether you didn’t understand it
But that’s the point. Entry 1 is not possible, that is to be seen.