Hello, I would like to know what happens in this circuit when the switch is open while the capacitor is charging. Does any of the lamps light up, and which ones?
I thought that no current could flow through the capacitor during charging, so no light would light up. Where am I wrong?
(2 votes)
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When the switch is open, C is charged and the red LED lights up shortly until the charging process is complete:
If you close the switch, C will be discharged via the green LED – it will therefore light up briefly:
Is it flowing through the capacitor during charging? How’s that going?
Perhaps you are irritating that the current apparently flows through C, although there is no conductive connection between the plates. The current flows to the left into the one plate – there positive charges accumulate. On the other hand, positive charges flow out of the right plate – there are then missing positive charges, this becomes negative. However, at no time are flowing charge carriers between the plates. It looks like the current flows through C. If the change in the electrical field strength D is also considered as a current (shift current density in contrast to the line current), the world is again in line. Then you have a continuous current flow. But this picture is not important for understanding. It is only important that in the case of a capacitor the current flowing into one end is always equal to the current flowing out at the other end. If this were not the case, the capacitor would charge itself as a whole, which is not possible.
How else is he supposed to charge himself? If loads are stored on the plates, they must come from somewhere. Only one power can transport loads. Somehow I don’t understand what you mean. You know what a capacitor does?
thank you, that was my problem
During charging and unloading, the current flows. If the capacitor is full, then no more current flows. A capacitor for alternating currents is therefore more permeable than for direct current.
I’ve been here forever, but I’d guess that the green LED lights up. Until the capacitor is “full”.