Do oxygen particles all move at the same speed at the same temperature?
Is this the case, or are there differences there as well?
Hello, I have an assignment about mass percent. Calculate the iodine content in mass percent in the food coloring erythrosine B (C20H6I4Na2O5) So first I calculated the molar mass of erythrosine B. M= 879.828 g/mol Then I calculated the molar mass of iodine in erythrosine B. 4 * 126.90 g/mol = 507.6 g/mol and in…
Hello, can anyone tell me what a titration curve of a polyprotonic acid looks like in conductometry?
Please I can not find on the Internet
I don't quite understand. Do they enter the glass bulb through the dark blue opening or through the heating coil?
Because I put ice cubes in there and then a lemon-flavored magnesium tablet and that takes longer than without ice?
Oxygen particles do not always move at the same temperature at the same speed.
The speed of particles in a gas (also air is a gas!) depends on various factors, such as temperature, pressure and mass of the particle. In an ideal gas, however, the particles move on average at the same speed, whereby the speeds of the individual particles vary within certain limits.
Please see Alex Lechner’s very good answer.
When the thermodynamics is about a lot of molecules, the term “DURCHSCHNITT” and also otherwise the statistics are central. The speed of individual molecules in the gas may also vary.
This may be difficult to understand or it may have an illogical effect, but rippers with a high inherent speed are possible.
A somewhat slanted example:
Let’s say that the billions of people on Earth can hop up at the stand for about 20 to 50 cm. But any miracle child can jump up 1000 km. Never mind. Go! The average is … 🙂
No, their speed is not identical, but obeys the Boltzmann distribution.
If you’re still going to school, you don’t have to understand everything in detail. It’s enough if you look at the colorful charts here and understand what they say. (Chemie High Level)
https://www.tec-science.com/de/thermodynamic-waermelehre/kinetische-gastheorie/maxwell-boltzmann-distribution/
VG
No. There’s always a few outliers.