Different sums after division?
Unfortunately, the headline doesn't address my question at all….
I have the following problem. Imagine two rows of numbers with the sum at the end, for example:
1 5 7 9 6 3 Total 31
3 7 1 3 9 5 Total 28
If you form the ratio from this, i.e. always divide the upper number by the lower one, then this series looks rounded like this: 0.34 0.71 7 3 0.67 0.6 Total 1.1
According to my logic, the sum of 1.1 should also be the sum of the numbers before it, but the actual sum would be much larger… Why is that? I don't understand.
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This is basically the same problem many pupils have in breaking.
The following shall apply: NOT:
Instead, you have to put the fractures on the same denominator, then…
… to be able to use.
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Let’s try a clear example…
If you add 3 sixth pieces of a pizza to 2 sixth pieces of a pizza. Then you obviously have 5 sixth pieces.
Then there are not suddenly (because of 6 + 6 = 12) twelfth pieces. You don’t have 5 twelfth pieces. Right?
That’s what you have not 2/6 + 3/6 = (2 + 3)/(6 + 6) = 5/12. One then has 2/6 + 3/6 = (2 + 3)/6 = 5/6.
Thank you, I had the problem in a completely different context and if I imagined it as a break, it makes sense… Thank you!
Because dividing doesn’t work like that!
Simple paper:
Thank you!
Because your assumption is wrong. Breaking bill doesn’t work like that. a/b+c/d is not the same as (a+c)/(b+d).
Because the basic assumption is bullshit
You can’t just separate a break and then add
(m+n)/(y+z) is not equal to (m/y)+(n/z) To add fractures, you need to expand them and bring them to a denominator.