Determine mass?
Hello,
Is there a scale that can measure mass (not weight)?
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Mass and weight is not the same. Thus, an astronaut on a space station, for example, cannot have a weight, although its mass is by no means zero.
Bar scales or usual kitchen scales use the weight (i.e. the normal force) of gravity to estimate the mass of a body. However, this is falsified in the earth’s atmosphere (lifting/inhomogeneity of the gravitational field) and can also not be used in the weightlessness.
What can be done to measure as accurately as possible a pure mass is, for example, a scale which measures the mass on the basis of the required force by means of an acceleration. This is also what I mean at the ISS, where astronauts hang on a construction that turns, which can then be closed to the mass due to the torque. This is still not exactly but rather goes in the direction of a general method for mass determination.
Measuring is a comparison of an unknown measured variable with a known measured variable.
Measuring a mass is the comparison of an unknown mass with a known mass by means of a classical mechanical scale. These scales are lever scales equipped with two weighing trays. The balance is brought into equilibrium by means of calibrated comparative masses (wages). The comparison mass does not have to be exactly as large as the unknown mass to be measured if the lever is designed accordingly (e.g. decimal scale). With these scales, the measurement result is not dependent on gravity. These scales can consequently be used for any desired celestial bodies.
LG H.
Nevertheless, the result of such scales is not entirely correct. On Earth, for example, the influence of the atmosphere in the form of e.g. buoyancy is still in effect.
I’ll talk to the seller about this when I buy the next gold bar.
in the formulation, I suspect that the scale should also indicate the correct mass on the moon (because on the earth, every commercial scale is doing under the assumption of a certain gravity acceleration). For this purpose, a beam balance with comparative weights of known masses can be taken.
the mass IST almost the weight.
it is also indicated in kg. a zenter kartoffeln e.g. has the mass of 50 kg
on earth, with a grvitation of 9.81 m/s2, this corresponds to a weight force of about 490 Newton.
Lg, Anna
The mass is in no case the weight
Physically, the difference is of course important. In practical everyday life is usually neglected. See my following answer to the technique of scales.
Then explain to me the difference between the mass that has a Zentner potato, that is 50 kg, and the weight, of a sack of cement, also 50 kg.
Lg, Anna
the weight CRAFT and also only on earth.
The weight of a sack of cement would not be 50kg but about 500N. Weight is simply the force that acts on the support in the vertical direction due to gravity. In the atmosphere of the earth, for example, gravity also comes to the buoyancy, which is why objects are lighter (not more massless!) than if there were no atmosphere.
The mass is no weight
Of course! All beam scales determine the mass via a comparison mass. I didn’t see any other scales in my childhood. In the kitchen stood a small bar scale for food preparation and at the coal dealer stood the large bar scale. It was also a personal scale. Even at my post office in Berlin, I still saw small beam scales in the 1980s, on which the post officer placed the enveloped letter on the plate of one side of the bar and on the opposite side small weights as Reference mass. According to this principle, even on the moon the letter mass would have determined correctly.
In the school’s physics lab you find so-called. “Feder scales” with spiral spring to measure force. In recent years, e.g. Force knives with strain sensors. So: Only comparatively modern scales do not allow the direct measurement of the mass!
Defined
Yes here: Measuring the mass of bodies
The mass of bodies is measured using scales. There are very different designs of such scales, for example beam scales, dish scales, kitchen scales or electronic scales.
super, then you could answer your question yourself