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What you need to know by heart:
If two straight lines are perpendicular to each other, the two slopes are:
m2 = -1
This can be solved according to m2:
m2 = -1/ m1
with m1= gradient of f(x) = -1/3 follows from this:
m2 = -1 / -(1/3) = -1 * -3 = 3
Therefore, the approach for h(x):
h(x) = 3x + b
b we get out with P(1/5):
5 = 3 * 1 + b
b = 5 – 3 = 2
This is the solution:
h(x) = 3x + 2
This looks like a graph:
Orthogonal means vertical. If a straight line h(x) is perpendicular
to f(x) and f(x) has the slope m, h(x) has the slope -1/m.
Now you have the gradient of the sought straight lines and a
Point is given, you can determine the straight line equation.