Combustion of butan-2-ol?

Maja18251ByMaja18251

Hello everyone,

I can't get any further with the following reaction equation:

C4H8O + O2 ——> CO2 + H2O

How do I balance both sides to make it correct?

Thank you in advance

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indiachinacook
indiachinacook
1 month ago

A; first we note that all butanols have the formula C4H10O. Then we write to:

C4H10O + ? O2 ⟶ ? CO2 + ? H2O

Only four CO2 can be left from the four C atoms, and only five H2O can be left from the ten H atoms:

C4H10O + ? O2 ⟶ 4 CO2 + 5 H2O

If we control the O-atoms, we note that on the right there are 4⋅2+5=13 of them, on the right of a butanol molecule, so there are 12 O-atoms missing. We can compensate for this with six O2 molecules, and it was.

C4H10O + 6 O2 ⟶ 4 CO2 + 5 H2O

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