chemie/ titration?

hier ist eine Frage, die ich nicht wirklich verstehe, warum es so ist… beim c)

Mein Lehrer hat als Indikator Thymolblau benutzt aber ich verstehe nicht warum, denn ich bekam als pH-Wert 3,4 und das ist eine Salpetrige Säure und wenn ich die Tabelle von Indikatoren sehe, macht es für mich gar keinen Sinn warum wir Thymolblau benutzen…

Hier ist die Tabelle, mit dem wir arbeiten:

ich würde zum Beispiel Methylorange benutzen…

kann mir irgendjemand von Chemieexperten helfen?

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indiachinacook
1 year ago

Here you have the titration curve, calculated with 12 ml of 1.75 mol/l HNO2 with 1 mol/l NaOH. You can see that the acid is mostly (98.7%) undissociated (red color) at the beginning and is deprotonated in the course of titration to the nitrite (blue). The half equivalence point (pH=pKa=3.4) is 10.5 ml, and the equivalence point (pH=8.65) is 21 ml consumption, with a pH jump of ≅6 to ≅12.

If you carry out the titration with an indicator, it should change in the range from 6 to 12; in your list this applies to bromothymole blue (6.0–7.6), phenolphthalein (8.2–10.0) and thymolphthalein (9.3–10.5). Of these three, phenolphthalein is the best choice because the envelope area is exactly in the middle of the jump area. Thymolblau (8.0–9.6) is also very suitable.

botanicus
1 year ago

It can be seen from your drawing that the APP is about 9. So you need an indicator to change. Thymolblau does this (but does not stand at all in your table). With phenolphthalein it should also go halfway.

botanicus
1 year ago
Reply to  Hiereinstudent

What?

botanicus
1 year ago

Yes, of course. I already wrote that in my first answer. But I don’t know phenol purple. Phenolphthalein is the substance.

botanicus
1 year ago

There’s no Thymolfarblos. You can use any indicator whose envelope point (color change) is in the area of the equivalence point.