CHEMIE: Redoxreihe der Metalle?
Hauptproblem:
Ich verstehe nicht warum Natrium (Na) und Goldoxid (AuO) miteinander reagieren können, wenn beispielsweise Magnesiumoxid und Gold oder Zinkoxid und Silber *nicht* miteinander reagieren können.
Nebenproblem:
Hab mirs jetzt so erklärt, dass wenn die Elemente der Reihe weiter auseinander sind, nicht bzw. nicht gut miteinander reagieren können. Und wenn sie nah beieinander sind sie gut reagieren. Richtig so?
Sodium is unpredictable and connects easily with oxygen. In other words, it oxidizes easily or emits electrons easily. Gold is noble and responsive, there are, if at all, electrons only disgusting.
The oxygen that absorbs electrons does not matter which metal these electrons originate from. Since sodium emits light electrons, it is oxidized instead of the gold and the gold is reduced to the pure metal by taking over the electrons of sodium.
In the appendix you will find a table which shows how noble (positive) or unedged (negative) metals are. The less noble metal is oxidized (bonded with oxygen) and the more noble metal is reduced. If the less noble metal is already oxidized, no reaction takes place (magnesium oxide and silver).
https://de.wikipedia.org/wiki/electrochemical_voltage series#electrochemical_voltage series
Chemotustra has already given you the answer that your likely teacher wants to raise. However, because I am a spoiler, I must point out that the reaction is impossible because there is no AuO gold oxide; there are only Au2O and Au2O3.
the AuO was not meant stoichiometric on my part, but should only stand for “gold oxide”
Your thoughts know something about your explanation. In the REDOX series, it is about which element the unedle is and which the noble.
Thus, metallic Na is very reactive (undelivery) and removes the oxygen from the AuO and becomes the sodium oxide. The AuO becomes formal to metallic, noble Au.
On the other hand, the unedle Mg is already present in oxidized From as MgO. Why should an oxide react with a noble metal such as Au or Ag?