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Es ist Al(OH)3 ⇌ Al3+ + 3 OH–
Das Löslichkeitsprodukt KL von Aluminiumhydroxid ist KL = c(Al3+) · c3(OH–)
Aus der chemischen Gleichung ist ersichtlich, dass 3c(Al3+) = c(OH–)
Dann folgt KL[Al(OH3)] = 3c(Al3+) · c3(OH–) = 3c4
Gegeben ist das Löslichkeitsprodukt von Aluminiumhyroxid:
KL = 5 · 10-33 mol4/L4
Du kannst jetzt c(Al3+) und die Masse dieser Ionen berechnen.