ByDilo3333
Hello,
I've been sick recently, and none of my classmates tell me what to do, even when I ask. Unfortunately, that's the kind of competitive nature of high school (I'm taking advanced chemistry and I'm not particularly good at it). I missed the topic of aromatics. I need 1b) and c), and unfortunately, I don't understand how to proceed.
In 1a) I have: 2 C6H6 + 15 O2-> 12CO2 +6 H2O
(1 votes)
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An Cyclohexen wird sich das Brom elektrophil addieren, Du bekommst also trans-Dibromcyclohexan (die Doppelbindung verschwindet).
C₆H₁₂ + Br₂ ⟶ C₆H₁₂Br₂
Mit Benzol reagiert Brom nur in Gegenwart eines Katalysators (z.B. wasserfreies FeBr₃). Dann tritt elektrophile Substitution ein, Du bekommst also Brombenzol (ein H wird durch Br ersetzt), und die „Doppelbindungen“ bleiben alle erhalten:
C₆H₆ + Br₂ ⟶ C₆H₅Br + HBr.
Eher elektrophil, oder?
Ja, Du hast recht, ich war konfus.