Chemistry homework help?
Can someone help me with these tasks and explain them as simply as possible?
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How does the boiling point relate to the molar mass of alkanes?
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You can calculate it with the molar mass M (PSE) and N=m/M (scoff quantity is the mass through the molar mass). Then you do c=n/V (concentration is quantity of substance by volume)
Then you can calculate the poh value with ph=-log c. You get the pH value when you make 14 – the value.
pH = 14-pOH
40 g molar mass NaOH
2.5 g/40 g = 0.0625 mol
c= n/V 0.0625 / 0.01l = 0.625 mol / l
-log c (OH)=0.2 / to pH value 14-0.2=13.8 as pH value
Right?
Perfect thanks:)