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PWolff
2 years ago

I don’t understand that.

The first sentence suggests that you should either examine whether there is an explosion or explain why there is an explosion, but it is not asked in the second sentence.

In the chlorination of methane there are several partial reactions which follow one another. Therefore, I interpret “a reaction after strong exposure” to the initial reaction. That is:

What happens when the mixture is exposed? Why is this reaction going off and not another?

Possibly/presumably, the subsequent reactions are also expected, i.e. which reactions take place next and how the products of the initial reaction trigger the subsequent reactions.

Research https://www.google.com/search?q=chlorination+methane services http://www.chemgapedia.de/vsengine/vlu/vsc/de/ch/12/oc/vlu_organik/radikale/substitutionsmech.vlu/Page/vsc/de/ch/12/oc/radikale/subst_mechanik/subst_mechanik.vscml.html

ChemLuis
2 years ago

Methane is free-radically chlorinated by means of Cl2 (chlorogas). This means that the Cl2 molecule is split into two Cl• radicals. This homolytic cleavage of the Cl2 molecule takes place by light of a specific wavelength range.
When the correct wavelength (so that correct energy) of electromagnetic radiation strikes the reaction mixture (by exposure) the reaction is initiated. The light cleaves the Cl2 molecules homolytically, highly reactive chlorine radicals are formed which gradually chlorinate the methane with the formation of hydrochloric acid.