Hello, I'm currently studying forces as vectors in physics. I came across the following problem:
I calculated this using cosine as follows.
I've basically enlarged the vector arrows to create a triangle with right angles. Is this allowed? Thanks for looking 🙂
(1 votes)
Loading...Hello, so the topic is heat capacity, and the task is: In winter, a concrete bridge is 270m long, 16m wide, 1.8m thick, and has a temperature of -30°C. In summer, it has a temperature of 80°C. Calculate the length in summer and the amount of heat it absorbs. The specific heat capacity was also…
I have the following task: I'm supposed to calculate it using the law of conservation of energy. Friction is taken into account (fglide = 0.301), and I'm supposed to calculate the speed at Z. I've done the calculations many times, but every time I get 36 m/s, the result is exactly half, so 18 m/s….
I have to write an assignment tomorrow. I don't understand the task. I urgently need help. Task: Give the coordinates of the missing vertices of a square pyramid with A(2,3,2) and B (2,6,2) with a height of 5cm. So you look for D and C. That gives 5, 6, 2 for D and 5, 3,…
Which 3 formulas are wrong?🤔
Hello, what is the answer to task 2 and why? And is task 1 correct? Thanks for all the answers!
Only the length of the green vector with F=400 N is given. It must not be extended… except for a new scale. The two red vectors are not given from their amount, but only from their direction. The length is to be determined, which will then also change its length.
For your account: the solutions for F1 and F2 are not correct yet. It must apply
2 Equations for the two unknowns F1 and F2. The second equation must apply because otherwise a force component perpendicular to the force F acts.
PS: I now understand what you mean by “extending” the vector arrows. Projecting F to F1 and F2 is, however, not sensible; the F1 and F2 thus obtained do not add vectorially to the force F. F1 and F2 have to form a parallelogram whose diagonal is equal to F–the angles are generally not perpendicular.
On the one hand it depends on what the drawing is supposed to represent and on the other what you mean to extend.
Of course, you may use auxiliary lines in each drawing, but if the drawing is to depict the vectors themselves and not only sketch the vectors, of course you must not extend the vectors.
Take the force F as a hypotenuse, you catch F1. So much is right. Since both angles together result in 90°, you can move F2 as a counter catheter of Angle Alpha. Then apply the phrase of Pythagoras.
Your calculations are correct. And all vectors yield a rectangular triangle. What’s the problem now?
I don’t quite understand what vector arrows mean, but the calculation is correct.
Vectors usually express a numerical value by their length and are Length and direction defined: You can’t just extend it like that.