ByManscheJ
Hello,
My brother has an electrical engineering exam in two weeks, and unfortunately, I can't solve the problem myself. Can someone explain to me how to calculate I2 using the superposition theorem? The result should be 1.5A.
(1 votes)
Loading...Is it possible to locate lost RFID cards or transponders (13.56 MHz) using, for example, a powerful reader (a type of metal detector for RFID)? Are such devices available for purchase and over what range would they work?
This concerns a tracking system for a solar system or the suspension of tracking at temperatures below 4° C in order to avoid damage caused, for example, by frozen joints. Can anyone recommend something (e.g. a thermistor) and know the resistance value of a 100k thermistor at 4° C and the other resistance values of…
I want to "tinker" with something, but I don't know where to get parts. I've already bought diodes, resistors, etc., but where can I get scrap to recycle? Free is best. I can forget about the neighborhood. LG
Why is it more difficult to construct a robot that can navigate the physical world and interact with and manipulate objects in it (grasp, operate, etc.) than to build a machine that is capable of beating the world's best chess players or breaking complex mathematical operations?
Hello fishing friends I'd like to get an E-Rider kayak from Savage Gear. Does anyone have experience with this kayak? Which engine is ideal? There are several manufacturers: Fox, Minn Kota, Savage Gear, etc. Thanks
You calculate it in two duches:
I understood the part shortening the voltage and current sources. I’m sorry if I don’t like anything because I always get something wrong
How do you know what you do wrong?
I built more crap than you…
But in the future, don’t put the picture in a landscape format.
Thank you for your help.
I meant the third is right. At the second, you’ve got yourself out.
the second is correct, because I swapped R1 and R2.
The second thing is wrong with you: it comes out 0.357A
It’s just a scary crochet and banged without a system.
The first I2 is OK.
The second where only the left power source is active: you write
I2 = 1*18(10+18)
?
that would be
I2 = I01*R1/(R23+R1) = 1*2/28=71.43mA
What you did: You counted the case where only the upper power source is active, but with the wrong current 1A, instead of 2A…
So, there’s nothing to fit, go in and do it clean and tidy… that’s pure slutty!
It’s coming out.
I2(ges) = 642,8mA
I’ve added the route up there. I hope you can see it
Overlay means that you consider each “power driver” individual. That is to say, each source is considered separately so that the current which leads through it a source can be determined. The resultant current in the circuit is then added as a sign.
(1) – Only U0 active. I01 and I02 in idle (open).
The current I2 is equal to the total current of the circuit. We set the current direction from case (1) as shown.
(2) – Only I01 active. I02 in idle. U0 short circuit.
The current I2 in this case is obtained via the current divider.
We later pay attention to the fact that I2(2) flows against I2(1).
(3) – Only I02 active. U0 short circuit.
Here again power dividers.
Now we add all the substreams to the right sign.
I swapped R1 and R2, your result is true
I criticized the questioner about slutty and was in the end self sloppy 😅
ANNEX This was also partly due to the image rotated through 90°, as I had to turn my head 😅
We cook all with water 🙂
Thank you for the detailed answer.