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(b)
The straight line g passes through the zero point and has the gradient 40/100 = 2/5, therefore g(x) = 2/5x
For f(x) = ax2 + bx + c applies
f(0) = 0 –> c = 0
f'(100) = 200a + b = 0
f(100) = a1002 + 100b = 40
From the last two equations follows a = -1/250, b = 4/5
##
The area of the entire distribution is:
Integral[0,100] f(x) dx = 8000/3
Remove the surface of the triangle:
8000/3 – 40*100/2
Then multiply with the length of the sprinkling:
(8000/3 – 40*100/2)*1000 = 2000000/3 m3
Sure.
Show your solutions as well as the notes of the teacher, and then we will get it.