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jjsch5
jjsch5
1 year ago

f'(x) = -3×2 + 5x + 2.5

0 = -3×2 + 5x + 2,5 | : (-3)

0 = x2 – 5/3x – 5/6

x1,2 = 5/6 -+ (100/144 + 5/6)^0.5

2
eineNutzer1In
eineNutzer1In
1 year ago

Use the midnight formula

so your functional structure is

ax2 + bx + c = 0

and you just put it in the

here the link if you need it more

https://studyflix.de/mathematik/midnightformel-einfach-erklaert-3948

1
jeanyfan
jeanyfan
1 year ago

So the zero in the bracket is wrong because you do not use 0 (which would mean) but set the equation equal to 0. When using the pq formula, always share the complete equation by the factor (including sign) which is in front of the x2.

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Tannibi
Tannibi
1 year ago

I don’t understand f'(0). If you are the NS of the Right
If you want to calculate terms, you need to use the pq formula
by -3 and then

x2 -5/3x – 2.5/3 = 0

Calculate.

1
jeanyfan
jeanyfan
1 year ago
Reply to  Tannibi

Will probably be incorrectly written with the f'(0) and f'(x)=0.

0