ByShabinga
Hello, I need help with a simple circuit: In order to get to Ua you would actually first have to combine the sources. Normally it would be a good idea to convert the 6 V voltage into a current source, but the 5 Ohm resistor is in parallel…. It is explicitly stated that the problem can only be solved by source conversion, no superposition theorem etc. Am I perhaps not seeing something that I should?
(2 votes)
Loading...Can anyone help me with number 1? Thanks
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Set the stitch equation for you red stitch:
-10V+I*1 Ohm +I*1 Ohm +6V+I*2 Ohm = 0
I*(4 Ohm) = 4V
=> I=1A
=> Ua = 1V
Nice thanks, but with conversion you can’t do anything or
The voltage sources 10V and 6V are in series. The 5 ohm resistance is irrelevant, because you can take out because it has no influence on the rest. The combined voltage is then 4V
https://de.wikipedia.org/wiki/Kirchhoffsche_regulations
Extract from the source
The Kirchhoffen Rules are used for network analysis in the context of electrical circuit technology. They divide into two basic and contiguous sets, the node set and the mesh set, and each describe the relationship between several electrical currents and between several electrical voltages in electrical networks. They were formulated in 1845 by Gustav Robert Kirchhoff after being discovered by Carl Friedrich Gauß in 1833.
This allows you to calculate all voltages, currents and resistors in your resistance network
Change the position of the 10V source with the 2 Ohm resistance, and then you’ll get the 2 Ohm and the 1 Ohm at the top.
You don’t have to consider currents at all if you want to calculate Ua. At the 5 ohm resistance, of course, the full 6V decreases, at the remaining series circuit the difference of 10V and 6V, Ua results from the resistance divider of the resistors above the 6V source.