Hello, we learned in school that -log(3-c(H3PO4)) = -log(0.731), but why is that? How do I get this 0.731? Also, I'm not entirely sure why we're calculating 3-c……. here. Does the 3 come from the 3 oxonium particles in the acid? And if so, why do we calculate this 3 minus the molar concentration?
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I don’t know what you’re talking about.
How big is the c0(H3PO4) in your example, so that you come to these numbers? By the way, this would result in a pH of 0.13, and this is too acidic for dilute phosphoric acid — even a 1 mol/l acid only comes to pH=1.1
By the way, the pH is calculated according to the formula
where Ka is the first acid constant of phosphoric acid (Ka≅7.11⋅10 ̄3 mol/l) and c0 is the weigh-in concentration — the formula only works for c0′′10 ̄7 mol/l.