Calculate the support force FA for the following information:
r1 = 343cm, r2 = 95cm, r3 = 201cm, r4 = 241cm
F1 = 1095 N, F2 = 764 N, F3 = 368 N
What is the support force FA?
(1 votes)
Loading...Is it possible, for example, to see in a 4-dimensional space what is in another space behind a closed wall? Or how do you imagine it?
Hi, I have a question: Are e pot and e kinetic the same? So, if I calculate e kin, does e pot give the same result? Because it always says e pot = e kin. Thanks for all the answers.
Hey, so I'm currently creating a value chart, and I did a quick Google search to see if I did it correctly. I noticed that everyone was putting time on the x-axis and distance on the y-axis. But I did it the other way around 😭 Is that a problem? Or is it still valid?
Hello, can someone please help me with this?
LG H.
Thanks for the help!
Set a moment equilibrium around the support point B and expose the equation according to Fa
I already found a solution, but I’m not sure it’s true. (608.76 N)
Yeah, that’s right. Only the accuracy on 2 places behind the comma is not meaningful, since you should round.
To exercise, you could now calculate the force Fb. What do you expect for this in principle in comparison?
Thank you for your help!
Well, I’m an e-technomist, but mechanic is also part of the e-tech study.
But here there are really well-declaring physicists or mechanical engineers, take alone as an example.
It is important for you to acquire as much exercise as possible (= routines and safety!!!) until then. You see, there are always many different approaches.
With timely exercise and learning you can really shine and clean up. Use this for you!
Good luck!
May I ask you if you generally know well in physics, as I am a student of 1 class Htl and have 2 weeks of physics test. As the main theme comes rotation and wanted to ask you if you know about it.(rail speed, moment of inertia, moment of rotation….)
Yeah, that’s all right.
My result is true. But for exercise purposes, you should work again with the other support and the associated torques…
I was just thinking. I swapped two lengths.
I’m coming to 1618 N. Anywhere?
Check it with a vertical balance of forces. So it’s not true.
Wait a minute.
As a result I get 1734 N. Is that right?
In addition, you only have positive torques on relatively large lever arms.
Then try the bearing point A as the pivot point.
I do not know so well in the subject, but I would think that the force is greater, as the distance to the forces is lower.