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Katschanks
2 years ago

In the case of task 3, the switches 4,5 and 7 must be set to ON because the HEX number 1A=26 is in DEC. Switch 4 is 16, switch 5 is 8 and switch 7 is 2. 16+8+2=26.

For task 4

1. B16 goes X to high

2.) X always goes to high

3.) X never goes to high

4.) X never goes high

Or is it meant that the hex numbers are available or are linked?

Katschanks
2 years ago
Reply to  Rainbowsun66

the small 16' stands for the number being a hexadecimal number, as in binary numbers there is a set 2.

At 4.) I have converted the hex numbers into dec and then into binary => there is a four-digit number eg A16 => 10 in dec => 1010 in bin and then the 0s and 1en are applied to the inputs Q0 to Q3. Q3 is the MSB and Q0 is the LSB

Katschanks
2 years ago
Reply to  Katschanks

The answer 4 is the right one and the right one.

Explanation: If you want to display the number 1, you need the right two LEDs called P1 and P2 are High so 1. Now, however, the point must always shine, P7 must be high (1) for each number. Say if you want to display the number 1 is the binary number: 10000110 this binary number is converted into HEX = 86.

Katschanks
2 years ago
Reply to  Rainbowsun66

I don't know exactly what you mean

Katschanks
2 years ago

I have already explained to you above 😉 => at achso and at Task 2….