How do I know which path the current takes?
For example, if I have the circuit here:
How do I know which path the current takes?
So does it just flow all the way around, or does it take the path I3 / I2 back to the voltage source?
How do I know? Maybe a stupid question, but I don't understand it.
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You know that because electricity takes all the paths. Why would he take the path through one resistance and not through another? Electricity isn't so picky when he finds a way, he takes it. Finds several, he also takes them without "I don't like this way today".
Why shouldn't the electricity take any given path?
For comparison: Which way does the water take from the barrel, into which 3 holes are drilled next to each other?
The current also flows simultaneously through all the routes offered.
Depending on the resistance, the current flows everywhere.
I took a lot of you treated Kirchhoff before you were given the task:
https://www.leifiphysik.de/electrizitaetslehre/complexere-circuits/grundwissen/kirchhoffsche-gesetz#:~:text=Knotenregel%3A%20in%20edem%20branchepunkt%20,%2B%20U%20n%20.
Kirchhoff is only helpful in this case and is not necessary to answer the question
Since the currents are explicitly recorded in color, I strongly assume that the exercise/task should treat the node rule.
The same voltage (case height) drops at all resistors.
The smaller the resistance value (the wider the constriction), the more current (water) flows.
The electricity 'takes' all three ways. He splits up according to resistance!
OK but why should 10V of the voltage source at the end also arrive at the voltage source? They're putting the voltage down?
ömm, voltage is energy per charge (U=E/Q). Behind the resistors the potential is virtually zero and the energy is converted into heat! In all three, the voltage drop is 10 V because they are connected in parallel.
The 'full' tension isn't coming! With a complete circulation in a mesh, the total voltage is zero, because the voltage is evaluated once positively and once negatively.
I wouldn't explain that normally.
@Spikeman197 but if the voltage at the resistors is lost, how does the full voltage then arrive at the end according to Kirchhoff again at the voltage source at the negative pole?
The current takes "every" way. The smaller the resistance, the greater the current flowing over it (at the same voltage)
all resistors are present at the same voltage, like this:
I1*R1 = I2*R2 = I3 *R3 = U