Why can methods be used in classes without prototypes in C++?
If I were to write hello() and output() as functions, I would need a prototype for output(). Why don't I need that in classes?
If I were to write hello() and output() as functions, I would need a prototype for output(). Why don't I need that in classes?
I now have basic knowledge of Java, but I don't know how to proceed. When I have a project idea, I have no idea how to start.
Hello, a quick question about the distributive law. One of my flashcards says the following: However, this example refers to a single operator within the parentheses. What happens if we have a term inside the parentheses? Example: (9 + 9 * 9) May I continue to apply the distributive law to the first factor, i.e….
Hey, this is the task: Could someone perhaps explain it using a) for example so that I can understand it? Thank you.
I have the task At first, I thought it would be useful to distinguish between cases where |a|>1 and |a|<1 would be more appropriate. The problem is, I'm stuck. If I have |a|>1, I'm closer to zero, but I can't really draw any conclusions from that.
I would like to learn C++ programming, but I have no programming experience yet. Do you have or know of any good YouTube tutorial videos, tutorial websites or books? If possible in English? I read about learncpp.com here. Is this website good for learning C++ programming?
Hello everyone, When I try to run a C# code in Visual Studio, the following error message appears: Could someone please help me with this? Best regards Valentine
Prototypes (usually written into the header) are necessary for the compiler with overarching modules or before definition/implementation of the function, so that the parameters can be passed by the latter in a manner that is safe from the type.
In the class class class, the methods are clogged/bonded and also defined and thus the compiler knows what to do/compile…