The general formula is:
12 H2O + 6 CO2 -> C6H12O6 + 6 H2O + 6 O2
But why does water form? (6H2O)
Isn't all the water being used or how should I understand that?
(1 votes)
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now, it must be taken into account that the O2, which is ejected, originates not from the CO2, but from the splitting of water.
And to push out 6 O2, not enough 6 H2O left. You need 12 H2O. Therefore, these 12 H2O must also appear left in the equation and 6 of them – formal – also right.
This equation was simplified by deducting -6 H2O on both sides, which Rolf said:
6 CO2 + 6 H2O → C6H12O6 + 6 O2
Thus it stands in many school books, as a simplified equation, but then suggests that the oxygen originates from the CO2. What is not the case now. The water on the right is nice when all primary and secondary reactions are included.
Therefore, your equation is the correct form. LG
Here it is explained in detail: https://zdb.uni-bielefeld.de/index.php/zdb/article/download/1703/1649
Strike the 6 H2O back, then it should be right
No, then the equation is no longer correct. One would have to remove 6 H2O on both sides so that the sum is correct.
But I don’t know whether the reaction would actually take place.
Joa, or something. At any rate no water comes out at the back