3 volt lamp to a 30 volt transformer?
I have no idea about electricity and only know that you need a resistor, but how do you find a suitable one and does it even work with 30 volts?
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On the bulb stands a power in Watt (W). If you divide them through 3V, you will receive the current as a result.
And if you now divide the excess 27 V through the current, you will receive the necessary resistance value for the resistance.
But: With such voltage differences, a resistance can become very warm. Therefore, you must also know its performance: P = U · I, so Watt = 27 V · Current.
Example:
Luminaires 3 V / 0.9 W
Current:
I = PL : UL = 0.9W : 3V = 0.3A
Pre-resistance:
R = UR : I = 27 V : 0.3 A = 90 Ω
Power resistance:
PR = UR · I = 27 V · 0.3 A = 8.1 W
If your lamp has three volts and three watts, you need a 27 ohm resistance and 27 watts. If not, look for the calculation of current, voltage and resistance ..
Greetings, Joe.
Yes. It is only necessary to install a resistor at which the 27 volts that are not required in this case or. "destroyed" (converted into heat).
To this end, however, it is necessary to inform how high the current is which the lamp needs.
If you know this, the story can easily be calculated by the Ohm's law.
It's okay, but it's nothing but a good idea.
Mr Electrican has already said so. You have to heat 9 times as much energy as the lamp needs.
You should know the power of the lamp. This allows you to calculate the current which flows at 3 volts. If 3 volts are to drop at the lamp, the pre-resistance must be sized such that 27 volts are present there. This can be calculated with the Ohmic Law.
Please
Did you pee in physics?
What is meant by performance?
Power in Watts (W). It's usually on the lamp.
The lamp is broken.
Don't worry, there are also points for stupid answers… 😎